CBSE 2025 · Region 1 · Set 1 · Q18 · 2 marks
In a diffraction experiment, the slit is illuminated by light of wavelength $\displaystyle 600$ nm. The first minimum of the pattern falls at $\displaystyle \theta=30^{\circ}$. Calculate the width of the slit.In a Young's double-slit experiment, two light waves, each of intensity $\displaystyle \mathrm{I}_{\mathrm{o}}$, interfere at a point, having a path difference $\displaystyle \frac{\lambda}{8}$ on the screen. Find the intensity at this point.
In a diffraction experiment, the slit is illuminated by light of wavelength $\displaystyle 600$ nm. The first minimum of the pattern falls at $\displaystyle \theta=30^{\circ}$. Calculate the width of the slit.
In a Young's double-slit experiment, two light waves, each of intensity $\displaystyle \mathrm{I}_{\mathrm{o}}$, interfere at a point, having a path difference $\displaystyle \frac{\lambda}{8}$ on the screen. Find the intensity at this point.
Marking-scheme solution
| \begin{itemize} \item[(a)] \begin{tabular}[t]{|l|l|} Calculating the width of the slit | $\displaystyle 2$ |
OR
\end{tabular}Wave OpticsDiffractionApplyvery_short_answermedium
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CBSE Class 12 Physics past-paper question from the 2025board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.