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Mathematics · 2025 · 1 mark

CBSE 2025 · Region 5 · Set 1 · Q15

The sum of the order and degree of the differential equation [1+((d y)/(d x))^2]^3=(d^2 y)/(d x^2) is:

The sum of the order and degree of the differential equation $\displaystyle \left[1+\left(\frac{d y}{d x}\right)^{2}\right]^{3}=\frac{d^{2} y}{d x^{2}}$ is :
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