CBSE 2023 · Region 5 · Set 3 · Q32 · 5 marks
Solve the following Linear Programming Problem graphically : Minimise : $\displaystyle \mathrm{Z}=60 \mathrm{x}+80 \mathrm{y}$ subject to constraints : \[\begin{aligned} & 3 \mathrm{x}+4 \mathrm{y} \geq 8 \\ & 5 \mathrm{x}+2 \mathrm{y} \geq 11 \\ & \mathrm{x}, \mathrm{y} \geq 0 \end{aligned} \]
Marking-scheme solution
$\displaystyle Z = 60x + 80y$$\displaystyle Z_B = 0 + 440 = 440$$\displaystyle Z_A = 120 + 40 = 160$$\displaystyle Z_C = 160$Minimum $\displaystyle Z = 160$ at all points of the line ACLinear ProgrammingLinear Programming Problem and its Mathematical FormulationApplylong_answermedium
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CBSE Class 12 Mathematics past-paper question from the 2023board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.