CBSE 2023 · Region 4 · Set 3 · Q28 · 3 marks
Solve the following linear programming problem graphically : Maximise $\displaystyle \mathrm{z}=5 \mathrm{x}+3 \mathrm{y}$ subject to the constraints \[\begin{array}{r} 3 \mathrm{x}+5 \mathrm{y} \leq 15 \\ 5 \mathrm{x}+2 \mathrm{y} \leq 10 \\ \mathrm{x}, \mathrm{y} \geq 0 \end{array} \]
Marking-scheme solution
Corner Points & Value of Z
$\displaystyle \mathrm{O}(0,0)$ & $\displaystyle 0$
$\displaystyle \mathrm{~B}(0,3)$ & $\displaystyle 9$
$\displaystyle \mathrm{C}(2,0)$ & $\displaystyle 10$
$\displaystyle \mathrm{P}(20 / 19,45 / 19)$ & $\displaystyle \frac{235}{19} \rightarrow \mathrm{Max}$
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CBSE Class 12 Mathematics past-paper question from the 2023board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.