SolveIt is under development
SolveItNCERT · CBSE · NEET
Question 40 / 69 · latest first
✓ Board-verified
Mathematics · 2024 · 1 mark

CBSE 2024 · Region 2 · Set 1 · Q2

Let f: R_+ →[-5, ∞) be defined as f(x)=9 x^2+6 x-5, where R_+ is the set of all non-negative real numbers. Then, f is:

Let $\displaystyle f: R_{+} \rightarrow[-5, \infty)$ be defined as $\displaystyle f(x)=9 x^{2}+6 x-5$, where $\displaystyle R_{+}$is the set of all non-negative real numbers. Then, $\displaystyle f$ is :
ShareWhatsAppTelegram

More from Relations and Functions

CBSE Class 12 Mathematics past-paper question from the 2024 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.