CBSE 2025 · Region 7 · Set 3 · Q24 · 2 marks
For a Linear Programming Problem, find min $\displaystyle \mathrm{Z}=5 \mathrm{x}+3 \mathrm{y}$ (where Z is the objective function) for the feasible region shaded in the given figure.
(Note : The figure is not to scale)
Marking-scheme solution
| Corner Points | Value of $\displaystyle \mathbf{Z}=\mathbf{5 x}+\mathbf{3 y}$ |
| $\displaystyle \mathbf{A}(\mathbf{3}, \mathbf{2})$ | $\displaystyle \mathbf{2 1}$ |
| $\displaystyle \mathbf{B}(\mathbf{0}, \mathbf{5})$ | $\displaystyle \mathbf{1 5}$ |
| $\displaystyle \mathbf{C}(\mathbf{0}, \mathbf{3})$ | $\displaystyle \mathbf{9}$ |
Linear ProgrammingLinear Programming Problem and its Mathematical FormulationApplyvery_short_answermedium
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CBSE Class 12 Mathematics past-paper question from the 2025board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.