CBSE 2024 · Region 2 · Set 3 · Q22 · 2 marks
Find the value of $\displaystyle \sin ^{-1}\left(-\frac{1}{2}\right)+\cos ^{-1}\left(-\frac{\sqrt{3}}{2}\right)+\cot ^{-1}\left(\tan \frac{4 \pi}{3}\right)$.Find the domain of $\displaystyle f(x)=\cos ^{-1}\left(1-x^{2}\right)$. Also, find its range.
Find the value of $\displaystyle \sin ^{-1}\left(-\frac{1}{2}\right)+\cos ^{-1}\left(-\frac{\sqrt{3}}{2}\right)+\cot ^{-1}\left(\tan \frac{4 \pi}{3}\right)$.
Find the domain of $\displaystyle f(x)=\cos ^{-1}\left(1-x^{2}\right)$. Also, find its range.
Marking-scheme solution
The given expression $\displaystyle =\frac{-\pi}{6}+\left(\pi-\frac{\pi}{6}\right)+\frac{\pi}{6}$=\frac{5 \pi}{6}
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Inverse Trigonometric FunctionsBasic Concepts of Inverse Trigonometric FunctionsApplyvery_short_answermedium
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CBSE Class 12 Mathematics past-paper question from the 2024board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.