CBSE 2023 · Region 5 · Set 3 · Q22 · 2 marks
Find the value of $\displaystyle \tan ^{-1}\left[2 \cos \left(2 \sin ^{-1} \frac{1}{2}\right)\right]+\tan ^{-1} 1$.
Marking-scheme solution
$$\tan ^{-1}\left[2 \cos \left(2 \cdot \frac{\pi}{6}\right)\right]+\frac{\pi}{4}
=\tan ^{-1}\left[2 \times \frac{1}{2}\right]+\frac{\pi}{4}=\frac{\pi}{4}+\frac{\pi}{4}=\frac{\pi}{2}
$$
Inverse Trigonometric FunctionsProperties of Inverse Trigonometric FunctionsApplyvery_short_answermedium
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CBSE Class 12 Mathematics past-paper question from the 2023board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.