CBSE 2025 · Region 1 · Set 2 · Q24 · 2 marks
Evaluate $\displaystyle : \sin ^{-1}\left(\sin \frac{3 \pi}{5}\right)$
Marking-scheme solution
\[\begin{aligned}
\sin ^{-1}\left(\sin \frac{3 \pi}{5}\right) & =\sin ^{-1}\left(\sin \left(\pi-\frac{2 \pi}{5}\right)\right) \\
& =\sin ^{-1}\left(\sin \left(\frac{2 \pi}{5}\right)\right) \\
& =\frac{2 \pi}{5}
\end{aligned}
\]
Inverse Trigonometric FunctionsProperties of Inverse Trigonometric FunctionsApplyvery_short_answereasy
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CBSE Class 12 Mathematics past-paper question from the 2025board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.