Equations of sides of a parallelogram ABCD are as follows: AB: (x +1)/1=(y -2)/-2=(z -1)/2 BC: (x -1)/3=(y +2)/-5=(z -5)/3 CD: (x -4)/1=(y +7)/-2=(z…

Equations of sides of a parallelogram ABCD are as follows : $\displaystyle \mathrm{AB}: \frac{\mathrm{x}+1}{1}=\frac{\mathrm{y}-2}{-2}=\frac{\mathrm{z}-1}{2}$ $\displaystyle \mathrm{BC}: \frac{\mathrm{x}-1}{3}=\frac{\mathrm{y}+2}{-5}=\frac{\mathrm{z}-5}{3}$ $\displaystyle \mathrm{CD}: \frac{\mathrm{x}-4}{1}=\frac{\mathrm{y}+7}{-2}=\frac{\mathrm{z}-8}{2}$ $\displaystyle \mathrm{DA}: \frac{\mathrm{x}-2}{3}=\frac{\mathrm{y}+3}{-5}=\frac{\mathrm{z}-4}{3}$ Find the equation of diagonal BD .