SolveItNCERT · CBSE Boards

CBSE 2025 · Region 6 · Set 1 · Q20 · 1 mark

Assertion (A) : Let $\displaystyle \mathrm{f}(\mathrm{x})=\mathrm{e}^{\mathrm{x}}$ and $\displaystyle \mathrm{g}(\mathrm{x})=\log \mathrm{x}$. Then $\displaystyle (\mathrm{f}+\mathrm{g}) \mathrm{x}=\mathrm{e}^{\mathrm{x}}+\log \mathrm{x}$ where domain of ( $\displaystyle \mathrm{f}+\mathrm{g}$ ) is R . Reason $\displaystyle (R): \quad \operatorname{Dom}(\mathrm{f}+\mathrm{g})=\operatorname{Dom}(\mathrm{f}) \cap \operatorname{Dom}(\mathrm{g})$.

Relations and FunctionsTypes of FunctionsUnderstandassertion_reasoneasy

More from Relations and Functions

CBSE Class 12 Mathematics past-paper question from the 2025board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.