Assertion (A): Let f ( x )= e^x and g ( x )= log x. Then ( f + g ) x = e^x + log x where domain of ( f + g ) is R. Reason (R): Dom ( f + g )= Dom ( f…

Assertion (A) : Let $\displaystyle \mathrm{f}(\mathrm{x})=\mathrm{e}^{\mathrm{x}}$ and $\displaystyle \mathrm{g}(\mathrm{x})=\log \mathrm{x}$. Then $\displaystyle (\mathrm{f}+\mathrm{g}) \mathrm{x}=\mathrm{e}^{\mathrm{x}}+\log \mathrm{x}$ where domain of ( $\displaystyle \mathrm{f}+\mathrm{g}$ ) is R . Reason $\displaystyle (R): \quad \operatorname{Dom}(\mathrm{f}+\mathrm{g})=\operatorname{Dom}(\mathrm{f}) \cap \operatorname{Dom}(\mathrm{g})$.