Write the name and structure of a hexadentate ligand. 1 Why is [Ni(CN) 4]^2- square planar while [Ni(CO) 4] is tetrahedral? [Atomic number: Ni=28 ]

(a)Ethylenediamine tetraacetate ion /EDTA4- (b)Oxidation state of Nickel is +2,CN- being a strong ligand results in pairing of electrons,hybridization is dsp2,hence geometry is Square planar whereas in Ni(CO)4, oxidation sate of Nickel is 0(Zero),hybridization is sp3,hence geometry is tetrahedral. (Or Diagrammatic explanation for both)

CBSE 2025 · Region 5 · Set 3 · Q24 · 3 marks

(a)
Write the name and structure of a hexadentate ligand. $\displaystyle 1$
(b)
Why is $\displaystyle \left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}$ square planar while $\displaystyle \left[\mathrm{Ni}(\mathrm{CO})_{4}\right]$ is tetrahedral ? [Atomic number : $\displaystyle \mathrm{Ni}=28$ ]

Coordination CompoundsDefinitions of Some Important Terms Pertaining to Coordination CompoundsAnalyseshort_answermedium

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(a)
Write the name and structure of a hexadentate ligand. $\displaystyle 1$
(b)
Why is $\displaystyle \left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}$ square planar while $\displaystyle \left[\mathrm{Ni}(\mathrm{CO})_{4}\right]$ is tetrahedral ? [Atomic number : $\displaystyle \mathrm{Ni}=28$ ]

Marking-scheme solution

More from Coordination Compounds

(a)Write the name and structure of a hexadentate ligand. $\displaystyle 1$(b)Why is $\displaystyle \left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}$ square planar while $\displaystyle \left[\mathrm{Ni}(\mathrm{CO})_{4}\right]$ is tetrahedral ? [Atomic number : $\displaystyle \mathrm{Ni}=28$ ]

Marking-scheme solution

More from Coordination Compounds

(a)
Write the name and structure of a hexadentate ligand. $\displaystyle 1$
(b)
Why is $\displaystyle \left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}$ square planar while $\displaystyle \left[\mathrm{Ni}(\mathrm{CO})_{4}\right]$ is tetrahedral ? [Atomic number : $\displaystyle \mathrm{Ni}=28$ ]