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Chemistry · 2022 · 3 marks
Aldehydes, Ketones and Carboxylic AcidsChemical Reactions of Aldehydes, Ketones and Carboxylic Acids3 marksApplyshort answer
CBSE 2022 · Region 2 · Set 2 · Q7
(a) Write the equations involved in the following reactions: (i) Cannizzaro reaction (ii) Aldol condensation (iii) Hell-Volhard-Zelinsky reaction
(a)
Write the equations involved in the following reactions :
(i)
Cannizzaro reaction
(ii)
Aldol condensation
(iii)
Hell-Volhard-Zelinsky reaction
OR
(b)(i)
Which acid of each pair would you expect to be stronger ? Give reason.
(I)
$\displaystyle \mathrm{F}-\mathrm{CH}_{2}-\mathrm{COOH}$ or $\displaystyle \mathrm{Cl}-\mathrm{CH}_{2}-\mathrm{COOH}$
(II)
or
(ii)
Distinguish between Propanal and Propanone.
Marking-scheme solution
(a)(i)
$\displaystyle 2$ HCHO $\displaystyle \xrightarrow{\text{conc. OH}^-}$ HCOO$\displaystyle ^-$ + CH$\displaystyle _3$OH
(ii)
2CH$\displaystyle _3$CHO $\displaystyle \xrightarrow{\text{dil. NaOH}}$ CH$\displaystyle _3$—CH(OH)—CH$\displaystyle _2$—CHO
(iii)
CH$\displaystyle _3$—COOH $\displaystyle \xrightarrow[\text{H}_2\text{O}]{\text{Cl}_2/\text{P}}$ CH$\displaystyle _2$(Cl)—COOH
OR
(b)(i)
(I)
F-CH$\displaystyle _2$COOH, due to -I effect of F.
(II)
p-nitrobenzoic acid, due to -I effect of NO$\displaystyle _2$ group.
(ii)
Heat both the compounds with NaOH and I$\displaystyle _2$, propanone gives yellow ppt. of iodoform while propanal does not.
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