CBSE 2025 · Region 2 · Set 1 · Q23 · 3 marks
The electrical resistance of a column of $\displaystyle 0.05$ M NaOH solution of area $\displaystyle 0.8 \mathrm{~cm}^{2}$ and length $\displaystyle 40$ cm is $\displaystyle 5 \times 10^{3} \mathrm{ohm}$. Calculate its resistivity, conductivity and molar conductivity.
Marking-scheme solution
$\displaystyle \rho = \dfrac{RA}{l}$$\displaystyle = \dfrac{5 \times 10^{3} \times 0.8}{40}$$\displaystyle = 100\ \Omega\ \text{cm}$$\displaystyle \kappa = \dfrac{1}{\rho}$$\displaystyle = \dfrac{1}{100}$$\displaystyle = 10^{-2}\ \text{S cm}^{-1}$$\displaystyle \mathbf{\Lambda}_m = \dfrac{\kappa \times 1000}{C}$$\displaystyle = \dfrac{10^{-2} \times 1000}{0.05}$$\displaystyle = 2 \times 10^{2}\ \text{S cm}^{2}\ \text{mol}^{-1}$
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CBSE Class 12 Chemistry past-paper question from the 2025board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.