SolveIt is under development
SolveItNCERT · CBSE · NEET
Question 19 / 141 · latest first
✓ Board-verified
Chemistry · 2026 · 5 marks

CBSE 2026 · Region 2 · Set 1 · Q32

(A) (a) The conductivity of 0.1 mol L^-1 solution of NaC l is 1.06 × 10^-2 S cm^-1. Calculate its molar conductivity and degree of dissociation. 3 +…

(a)
The conductivity of $\displaystyle 0.1 \mathrm{~mol} \mathrm{~L}^{-1}$ solution of $\displaystyle \mathrm{NaC} l$ is $\displaystyle 1.06 \times 10^{-2} \mathrm{~S} \mathrm{~cm}^{-1}$. Calculate its molar conductivity and degree of dissociation. $\displaystyle 3$ + $\displaystyle 2$ \[\begin{aligned} & \lambda^{\circ} \mathrm{Na}^{+}=50.1 \mathrm{~S} \mathrm{~cm}^{2} \mathrm{~mol}^{-1} \\ & \lambda^{\circ}{ }_{\mathrm{Cl}}^{-}=76.5 \mathrm{~S} \mathrm{~cm}^{2} \mathrm{~mol}^{-1} \end{aligned} \]
(b)(i)
Following cell reaction occurs in a galvanic cell : \[2 \mathrm{Ag}_{(\mathrm{aq})}^{+}+\mathrm{Zn}_{(\mathrm{s})} \longrightarrow 2 \mathrm{Ag}_{(\mathrm{s})}+\mathrm{Zn}_{(\mathrm{aq})}^{2+} \mathrm{E}_{(\mathrm{cell})}^{\circ}=+1.56 \mathrm{~V} \] Predict the direction of flow of current.
(ii)
Differentiate between a primary battery and a secondary battery.
ShareWhatsAppTelegram

More from Electrochemistry

CBSE Class 12 Chemistry past-paper question from the 2026 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.