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Chemistry · 2025 · 3 marks
CBSE 2025 · Region 1 · Set 3 · Q22
Henry's law constant for CO_2 in water is 1.67 × 10^8 Pa at 298 K. Calculate the number of moles of CO_2 in 500 ml of soda water when packed under…
Henry's law constant for $\displaystyle \mathrm{CO}_{2}$ in water is $\displaystyle 1.67 \times 10^{8} \mathrm{~Pa}$ at $\displaystyle 298$ K. Calculate the number of moles of $\displaystyle \mathrm{CO}_{2}$ in $\displaystyle 500$ ml of soda water when packed under $\displaystyle 2.53 \times 10^{5} \mathrm{~Pa}$ at the same temperature.
Marking-scheme solution
pCO2 = KH ꭓCO2
KH = $\displaystyle 1.67$ x $\displaystyle 108$ Pa
pCO2 = $\displaystyle 2.53$ x $\displaystyle 105$ Pa
ꭓCO2 = pCO2 / KH
=$\displaystyle 1.51$ x $\displaystyle 10$-$\displaystyle 3$
ꭓ𝐶𝑂$\displaystyle 2$=
𝑛𝐶𝑂$\displaystyle 2$
𝑛𝐻$\displaystyle 20$
nH2O = $\displaystyle 500$/$\displaystyle 18$ = $\displaystyle 27.78$ moles
nCO2 =$\displaystyle 27.78$ X $\displaystyle 1.51$ X $\displaystyle 10$-$\displaystyle 3$ moles
= $\displaystyle 42.0$ X $\displaystyle 10$-$\displaystyle 3$ mol = $\displaystyle 0.042$ moles
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CBSE Class 12 Chemistry past-paper question from the 2025 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.