CBSE 2025 Β· Region 1 Β· Set 2 Β· Q22 Β· 3 marks
A solution containing $\displaystyle 15$ g urea (molar mass $\displaystyle =60 \mathrm{~g} \mathrm{~mol}^{-1}$ ) per litre of solution in water has the same osmotic pressure (isotonic) as a solution of glucose (molar mass $\displaystyle =180 \mathrm{~g} \mathrm{~mol}^{-1}$ ) in water. Calculate the mass of glucose present in one litre of its solution.
Marking-scheme solution
Ξ = CRT =
π€π΅RT
ππ΅π
Ο glucose = Ο urea
CG = CU
ππΊ
ππΊ=
ππ
ππ
π€πΊ
wG =
= $\displaystyle 45$ π
SolutionsColligative Properties and Determination of Molar MassApplyshort_answermedium
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CBSE Class 12 Chemistry past-paper question from the 2025board exam, with the answer as CBSEβs own marking scheme gives it. Where our answers come from.