Give reasons: (i) Ammonolysis of alkyl halides is not a good method to prepare pure primary amines. (ii) Aniline does not give Friedel-Crafts…

(i) Because it gives a mixture of amines which is difficult to separate.

(ii) Aniline is a Lewis base and it reacts with \(\displaystyle \mathrm{AlCl}_{3}\) to form a salt / N of aniline acquires positive charge with \(\displaystyle \mathrm{AlCl}_{3}\) and hence is a deactivating group.

(iii) Because of protonation of aniline / formation of anilinium ion which deactivates the ring.