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Chemistry · 2026 · 3 marks
CBSE 2026 · Region 2 · Set 3 · Q25
(a) Explain why [ Fe ( H_2 O )_6]^3+ is strongly paramagnetic whereas [ Fe ( CN )_6]^3- is weakly paramagnetic. [Atomic number of Fe =26 ] 2 + 1 (b)…
(a)
Explain why $\displaystyle \left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}$ is strongly paramagnetic whereas $\displaystyle \left[\mathrm{Fe}(\mathrm{CN})_{6}\right]^{3-}$ is weakly paramagnetic. [Atomic number of $\displaystyle \mathrm{Fe}=26$ ] $\displaystyle \mathbf{2} \boldsymbol{+} \mathbf{1}$
(b)
On the basis of crystal field theory, write the electronic configuration for $\displaystyle \mathrm{d}^{5}$ ion for which $\displaystyle \Delta_{0}<\mathrm{P}$.
Marking-scheme solution
(a)
In [Fe(H2O)$\displaystyle 6$] $\displaystyle 3$+, H2O is a weak field ligand, 3d electrons do not pair up.
Hence it is strongly paramagnetic.
Whereas in [Fe(CN)$\displaystyle 6$] $\displaystyle 3$−, cyanide ion is a strong field ligand, 3d electrons pair up
leaving only one unpaired electron. So it is weakly paramagnetic.
(b)
t2g3eg2
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