Explain [Co(NH 3) 6]^3+ is an inner orbital complex whereas [Ni(NH 3) 6]^2+ is an outer orbital complex. [At. No. Co=27, Ni=28 ]

In case of [Co(NH3)6 ]3+, presence of NH3, the 3d electrons pair up leaving two d orbitals empty to be involved in d2sp3 hybridisation forming inner orbital complex. In [Ni(NH3)6]2+, Ni is in +2 oxidation state and has d8 configuration, the hybridization involved is sp3d2 forming outer orbital complex.

CBSE 2025 · Region 2 · Set 2 · Q20 · 2 marks

Explain $\displaystyle \left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}$ is an inner orbital complex whereas $\displaystyle \left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}$ is an outer orbital complex. [At. No. $\displaystyle \mathrm{Co}=27, \mathrm{Ni}=28$ ]

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Explain $\displaystyle \left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}$ is an inner orbital complex whereas $\displaystyle \left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}$ is an outer orbital complex. [At. No. $\displaystyle \mathrm{Co}=27, \mathrm{Ni}=28$ ]

Marking-scheme solution

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