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Chemistry · 2025 · 2 marks
CBSE 2025 · Region 2 · Set 2 · Q20
Explain [ Co ( NH_3)_6]^3+ is an inner orbital complex whereas [ Ni ( NH_3)_6]^2+ is an outer orbital complex. [At. No. Co =27, Ni =28 ]
Explain $\displaystyle \left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}$ is an inner orbital complex whereas $\displaystyle \left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{6}\right]^{2+}$ is an outer orbital complex. [At. No. $\displaystyle \mathrm{Co}=27, \mathrm{Ni}=28$ ]
Marking-scheme solution
In case of [Co(NH3)$\displaystyle 6$ ]$\displaystyle 3$+, presence of NH3, the 3d electrons pair up leaving two d orbitals
empty to be involved in d2sp3 hybridisation forming inner orbital complex.
In [Ni(NH3)$\displaystyle 6$]$\displaystyle 2$+, Ni is in +$\displaystyle 2$ oxidation state and has d8 configuration, the hybridization
involved is sp3d2 forming outer orbital complex.
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