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Chemistry · 2023 · 1 mark
CBSE 2023 · Region 5 · Set 3 · Q3
Consider the following standard electrode potential values: Sn^2+_( aq ) +2 e^- → Sn_( s ) E^°=-0.14 V Fe^3+_( aq ) + e^- → Fe^2+_( aq ) E^°=+0.77 V…
Consider the following standard electrode potential values : $\displaystyle \mathrm{Sn}^{2+}{ }_{(\mathrm{aq})}+2 \mathrm{e}^{-} \rightarrow \mathrm{Sn}_{(\mathrm{s})} \mathrm{E}^{\circ}=-0.14 \mathrm{~V}$ $\displaystyle \mathrm{Fe}^{3+}{ }_{(\mathrm{aq})}+\mathrm{e}^{-} \rightarrow \mathrm{Fe}^{2+}{ }_{(\mathrm{aq})} \mathrm{E}^{\circ}=+0.77 \mathrm{~V}$ What is the cell reaction and potential for the spontaneous reaction that occurs?
Official answer
(B)
$\displaystyle 2 \mathrm{Fe}^{3+}{ }_{(\mathrm{aq})}+\mathrm{Sn}_{(\mathrm{s})} \rightarrow 2 \mathrm{Fe}^{2+}{ }_{(\mathrm{aq})}+\mathrm{Sn}^{2+}{ }_{(\mathrm{aq})} \mathrm{E}^{\circ}=+0.91 \mathrm{~V}$
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CBSE Class 12 Chemistry past-paper question from the 2023 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.