CBSE 2025 · Region 2 · Set 2 · Q23 · 3 marks

Calculate $\displaystyle \mathbf{\Lambda}^{\circ} \mathrm{m}$ for acetic acid and its degree of dissociation $\displaystyle (\alpha)$ if its molar conductivity is $\displaystyle 48.1 \Omega^{-1} \mathrm{~cm}^{2} \mathrm{~mol}^{-1}$. Given that \[\begin{aligned} & \mathbf{\Lambda}^{\mathrm{o}} \mathrm{~m}(\mathrm{HCl})=426 \Omega^{-1} \mathrm{~cm}^{2} \mathrm{~mol}^{-1} \\ & \mathbf{\Lambda}^{\mathrm{o}} \mathrm{~m}(\mathrm{NaCl})=126 \Omega^{-1} \mathrm{~cm}^{2} \mathrm{~mol}^{-1} \\ & \mathbf{\Lambda}^{\circ} \mathrm{m}\left(\mathrm{CH}_{3} \mathrm{COONa}\right)=91 \Omega^{-1} \mathrm{~cm}^{2} \mathrm{~mol}^{-1} \end{aligned} \]

CBSE Class 12 Chemistry past-paper question from the 2025board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.