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CBSE 2026 · Region 2 · Set 1 · Q23 · 3 marks

Calculate emf of the following cell at $\displaystyle 298$ K : $\displaystyle \mathrm{Sn}\left|\mathrm{Sn}^{2+}(0.001 \mathrm{M})\right|\left|\mathrm{H}^{+}(0.01 \mathrm{M})\right| \mathrm{H}_{2(\mathrm{~g})}(1$ bar $\displaystyle ) \mid \mathrm{Pt}_{(\mathrm{s})}$ Given : $\displaystyle \mathrm{E}^{0}{ }_{\mathrm{Sn}^{2+} / \mathrm{Sn}}=-0.14 \mathrm{~V}$, \[\mathrm{E}^{\mathrm{o}}{ }_{\mathrm{H}^{+} / \mathrm{H}_{2}}=0.00 \mathrm{~V}[\log 10=1] \]

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