Calculate emf of the following cell at 25 °C: Sn / Sn^2+(0.001 M ) ∥ H^+(0.01 M )| H_2( g ) (1 bar )| Pt_( s ) Given: E^°( Sn^2+ / Sn )=-0.14 V, E^°…

\(\displaystyle \mathrm{E}_{\text {cell }}=\mathrm{E}^{\mathrm{o}}{ }_{\text {cell }}-\frac{0.059}{2} \log \frac{\left[\mathrm{Sn}^{2+}\right]}{\left[\mathrm{H}^{+}\right]^{2}}\) \[\mathrm{E}_{\text {cell }}^{\mathrm{o}}=0-(-0 \cdot 14 \mathrm{~V})=0 \cdot 14 \mathrm{~V} \] \[\begin{aligned} & \mathrm{E}_{\text {cell }}=0 \cdot 14-\frac{0 \cdot 059}{2} \log \frac{(0 \cdot 001)}{(0 \cdot 01)^{2}} \\ & =0 \cdot 14-\frac{0 \cdot 059}{2} \log 10 \\ & =0 \cdot 14-0 \cdot 0295=0 \cdot 1105 \mathrm{~V} \text { or } 0.11 \mathrm{~V} \end{aligned} \]