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Science · 2026 · 3 marks
CBSE 2026 · Region 2 · Set 1 · Q37
The values of current $\displaystyle I$ flowing in a given resistor for the corresponding values of potential difference $\displaystyle V$ applied across the ends of resistor are given below in the table : $\displaystyle I$ (Amperes) $\displaystyle 0 \cdot 4$ $\displaystyle 0 \cdot 8$ $\displaystyle 1$•$\displaystyle 2$ $\displaystyle 1 \cdot 6$ $\displaystyle 2 \cdot 0$ $\displaystyle V$ (Volts) $\displaystyle 1$•$\displaystyle 2$ $\displaystyle 2 \cdot 4$ $\displaystyle 3.6$ $\displaystyle 4.8$ $\displaystyle 6.0$
Plot a graph between $\displaystyle V$ and $\displaystyle I$ and calculate the resistance of that resistor.
| $\displaystyle I$ (Amperes) | $\displaystyle 0 \cdot 4$ | $\displaystyle 0 \cdot 8$ | $\displaystyle 1$•$\displaystyle 2$ | $\displaystyle 1 \cdot 6$ | $\displaystyle 2 \cdot 0$ |
| $\displaystyle V$ (Volts) | $\displaystyle 1$•$\displaystyle 2$ | $\displaystyle 2 \cdot 4$ | $\displaystyle 3.6$ | $\displaystyle 4.8$ | $\displaystyle 6.0$ |
Marking-scheme solution
Resistance = Slope of V - I graph
\[\begin{aligned}
& \mathrm{R}=\frac{\mathrm{BC}}{\mathrm{AC}} \\
& \mathrm{R}=\frac{6.0-1.2}{2.0-0.4} \\
& \mathrm{R}=3 \Omega
\end{aligned}
\]
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CBSE Class 10 Science past-paper question from the 2026board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.