In a domestic circuit five LED bulbs are arranged as shown. The source voltage is 220 V and the power rating of each bulb is marked in the circuit…

(i) Bulb A glows

(ii) Bulbs B, C, D and E glow

(b) \(\displaystyle \mathrm{P}=\mathrm{V} \times \mathrm{I}\) \[\begin{aligned} & 11=55 \times \mathrm{I} \\ & \mathrm{I}=\frac{1}{5}=0.2 \mathrm{amp} \end{aligned} \]

(c) \[\begin{aligned} & \text { (i) Resistance of bulb } \mathrm{B}, \mathrm{R}=\frac{V}{I}=\frac{55 \mathrm{~V}}{0.2 \mathrm{~A}}=275 \Omega \\ & \text { (alternative formula for calculation } \mathrm{R}=\frac{V^{2}}{P} \text { ) } \end{aligned} \]

Bulb A will keep glowing with same brightness.

Other bulbs i.e., B, D and E will stop glowing.

Reason: