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Science · 2026 · 2 marks
CBSE 2026 · Region 4 · Set 1 · Q33
A fuse in electric circuit is rated $\displaystyle 4$ A. Can it be used with an electric heater of rating $\displaystyle 2$ kW, $\displaystyle 200$ V ? Explain your answer.How is an electromagnet made ? Write any two ways by which the strength of electromagnet can be increased.
A fuse in electric circuit is rated $\displaystyle 4$ A. Can it be used with an electric heater of rating $\displaystyle 2$ kW, $\displaystyle 200$ V ? Explain your answer.
How is an electromagnet made ? Write any two ways by which the strength of electromagnet can be increased.
Marking-scheme solution
(A)
\(\displaystyle \mathrm{I}=\frac{\mathrm{P}}{\mathrm{V}}\)
\[\mathrm{I}=\frac{2000}{200}
\]
\(\displaystyle \mathrm{I}=10 \mathrm{~A}\)
Current passing through electric heater is 10A which is much more than rated value (4A) of fuse. Hence fuse will melt and break the circuit. So, it cannot be used.
OR
(B)An electromagnet is formed by wrapping a current carrying insulated copper wire in the form of coil around a magnetic material like soft iron core. / By placing a magnetic material like soft iron as a core material inside the current carrying solenoid.
Strength of electromagnet can be increased by increasing the (i) Number of turns of coil
(ii) Current flowing through the coil.
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CBSE Class 10 Science past-paper question from the 2026board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.