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Mathematics · 2024 · 2 marks
CBSE 2024 · Region 2 · Set 2 · Q24
The vertices of a $\displaystyle \triangle \mathrm{ABC}$ are $\displaystyle \mathrm{A}(-2,4), \mathrm{B}(4,3)$ and $\displaystyle \mathrm{C}(1,-6)$. Find length of the median BD.
Marking-scheme solution
Mid-point of AC is D \(\displaystyle \left(-\frac{1}{2},-1\right)\)
Length of median BD
\[=\sqrt{\left(4+\frac{1}{2}\right)^{2}+(3+1)^{2}}=\sqrt{\frac{145}{4}} \text { or } \frac{\sqrt{145}}{2}
\]
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CBSE Class 10 Mathematics past-paper question from the 2024board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.