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Mathematics · 2026 · 1 mark
CBSE 2026 · Region 3 · Set 1 · Q18
The value of (1/2 tan^2 45^°- cos^2 60^°) is:
The value of $\displaystyle \left(\frac{1}{2} \tan ^{2} 45^{\circ}-\cos ^{2} 60^{\circ}\right)$ is :
Official answer
(C)
$\displaystyle \frac{1}{4}$
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CBSE Class 10 Mathematics past-paper question from the 2026 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.