The perimeter of a rectangle is 70 cm. The length of the rectangle is 5 cm more than twice is breadth. Express the given situation as a system of…

Let the length and breadth of rectangle be \(\displaystyle x\) and \(\displaystyle y\) respectively. ATQ \[x+y=35 \ldots \text{(i)} \] \[\text{and } x-2 y=5 \ldots \text{(ii)} \] Solving (i) and (ii), we get \(\displaystyle x=25\) and \(\displaystyle y=10\) Hence the length and breadth of rectangle are $\displaystyle 25$ cm and $\displaystyle 10$ cm respectively.