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Mathematics · 2025 · 3 marks
CBSE 2025 · Region 4 · Set 1 · Q29
(A) Prove that (cos A + sin A -1)/(cos A - sin A +1)= cosec A - cot A
(A)
Prove that $\displaystyle \frac{\cos \mathrm{A}+\sin \mathrm{A}-1}{\cos \mathrm{~A}-\sin \mathrm{A}+1}=\operatorname{cosec} \mathrm{A}-\cot \mathrm{A}$
OR
(B)
If $\displaystyle \cot \theta+\cos \theta=p$ and $\displaystyle \cot \theta-\cos \theta=q$, prove that $\displaystyle p^{2}-q^{2}=4 \sqrt{p q}$
Marking-scheme solution
\[\begin{aligned}
\mathrm{LHS} & =\frac{\cos \mathrm{A}+\sin \mathrm{A}-1}{\cos \mathrm{~A}-\sin \mathrm{A}+1} \\
& =\frac{\cot \mathrm{A}+1-\operatorname{cosec} \mathrm{A}}{\cot \mathrm{~A}-1+\operatorname{cosec} \mathrm{A}} \\
& =\frac{\cot \mathrm{A}-\operatorname{cosec} \mathrm{A}+\operatorname{cosec}^{2} \mathrm{~A}-\cot ^{2} \mathrm{~A}}{\cot \mathrm{~A}-1+\operatorname{cosec} \mathrm{A}} \\
& =\frac{(\operatorname{cosec} \mathrm{A}-\cot \mathrm{A})(-1+\operatorname{cosec} \mathrm{A}+\cot \mathrm{A})}{\cot \mathrm{A}-1+\operatorname{cosec} \mathrm{A}} \\
& =\operatorname{cosec} \mathrm{A}-\cot \mathrm{A}=\mathrm{RHS}
\end{aligned}
\]
\[\begin{aligned}
\text { LHS } & =p^{2}-q^{2} \\
& =(\cot \theta+\cos \theta)^{2}-(\cot \theta-\cos \theta)^{2} \\
& =[(\cot \theta+\cos \theta)+(\cot \theta-\cos \theta)][(\cot \theta+\cos \theta)-(\cot \theta-\cos \theta)] \\
& =2 \cot \theta \times 2 \cos \theta=4 \cot \theta \cos \theta
\end{aligned}
\]
\[\begin{aligned}
\text { RHS } & =4 \sqrt{p q} \\
& =4 \sqrt{(\cot \theta+\cos \theta)(\cot \theta-\cos \theta)} \\
& =4 \sqrt{\cot ^{2} \theta-\cos ^{2} \theta} \\
& =4 \sqrt{\cos ^{2} \theta\left(\operatorname{cosec}^{2} \theta-1\right)} \\
& =4 \sqrt{\cos ^{2} \theta \times \cot ^{2} \theta} \\
& =4 \cot \theta \cos \theta
\end{aligned}
\]
\[\therefore \text { LHS }=\text { RHS }
\]
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CBSE Class 10 Mathematics past-paper question from the 2025 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.