SolveIt is under development
SolveItNCERT · CBSE · NEET
Question 50 / 98 · latest first
✓ Board-verified
Mathematics · 2025 · 2 marks

CBSE 2025 · Region 6 · Set 1 · Q24

P is a point on the side BC of ABC such that ∠ APC =∠ BAC. Prove that AC^2= BC · CP.

P is a point on the side BC of $\displaystyle \triangle \mathrm{ABC}$ such that $\displaystyle \angle \mathrm{APC}=\angle \mathrm{BAC}$. Prove that $\displaystyle \mathrm{AC}^{2}=\mathrm{BC} \cdot \mathrm{CP}$.
ShareWhatsAppTelegram

More from Triangles

CBSE Class 10 Mathematics past-paper question from the 2025 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.