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Mathematics · 2023 · 1 mark

CBSE 2023 · Region 1 · Set 1 · Q9

$\displaystyle \left[\frac{3}{4} \tan ^{2} 30^{\circ}-\sec ^{2} 45^{\circ}+\sin ^{2} 60^{\circ}\right]$ is equal to

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CBSE Class 10 Mathematics past-paper question from the 2023board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.

[3/4 tan^2 30^°- sec^2 45^°+ sin^2 60^°] is equal to — CBSE Class 10 Mathematics 2023 | SolveIt