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Mathematics · 2023 · 3 marks
CBSE 2023 · Region 2 · Set 1 · Q31
In the given figure, O is the centre of the circle and QPR is a tangent to it at P. Prove that ∠ QAP +∠ APR =90^°.
In the given figure, O is the centre of the circle and QPR is a tangent to it at P . Prove that $\displaystyle \angle \mathrm{QAP}+\angle \mathrm{APR}=90^{\circ}$.
Marking-scheme solution
OA = OP
\[\therefore \text { In } \triangle \mathrm{OAP}, \angle \mathrm{OPA}=\angle \mathrm{OAP}
\]
\[\Rightarrow \angle \mathrm{OPA}+\angle \mathrm{APR}=90^{\circ}
\]
\[\Rightarrow \angle \mathrm{OAP}+\angle \mathrm{APR}=90^{\circ}
\]
Using (i)
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CBSE Class 10 Mathematics past-paper question from the 2023 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.