SolveIt is under development
SolveItNCERT · CBSE · NEET
Question 43 / 98 · latest first
✓ Board-verified
Mathematics · 2025 · 1 mark

CBSE 2025 · Region 3 · Set 1 · Q18

In the given figure, in Δ ABC, AD ⊥ BC and ∠ BAC =90^°. If BC =16 cm and DC =4 cm, then the value of x is:

In the given figure, in $\displaystyle \Delta \mathrm{ABC}, \mathrm{AD} \perp \mathrm{BC}$ and $\displaystyle \angle \mathrm{BAC}=90^{\circ}$. If $\displaystyle \mathrm{BC}=16 \mathrm{~cm}$ and $\displaystyle \mathrm{DC}=4 \mathrm{~cm}$, then the value of x is: Figure: CBSE Class 10 Mathematics 2025, Triangles
ShareWhatsAppTelegram

More from Triangles

CBSE Class 10 Mathematics past-paper question from the 2025 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.