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CBSE 2025 · Region 3 · Set 1 · Q18 · 1 mark

In the given figure, in $\displaystyle \Delta \mathrm{ABC}, \mathrm{AD} \perp \mathrm{BC}$ and $\displaystyle \angle \mathrm{BAC}=90^{\circ}$. If $\displaystyle \mathrm{BC}=16 \mathrm{~cm}$ and $\displaystyle \mathrm{DC}=4 \mathrm{~cm}$, then the value of x is: Figure: CBSE Class 10 Mathematics 2025, Triangles

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CBSE Class 10 Mathematics past-paper question from the 2025board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.