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Mathematics · 2023 · 4 marks
CBSE 2023 · Region 5 · Set 2 · Q38
In a pool at an aquarium, a dolphin jumps out of the water travelling at 20 cm per second. Its height above water level after t seconds is given by h…
In a pool at an aquarium, a dolphin jumps out of the water travelling at $\displaystyle 20$ cm per second. Its height above water level after t seconds is given by $\displaystyle \mathrm{h}=20 \mathrm{t}-16 \mathrm{t}^{2}$.
Based on the above, answer the following questions :
(i)
Find zeroes of polynomial $\displaystyle \mathrm{p}(\mathrm{t})=20 \mathrm{t}-16 \mathrm{t}^{2}$.
(ii)
Which of the following types of graph represents p(t) ?
(c)
(b)
(d)
(iii)
(a)
What would be the value of h at $\displaystyle \mathrm{t}=\frac{3}{2}$ ? Interpret the result.
OR
(b)
How much distance has the dolphin covered before hitting the water level again ?
Marking-scheme solution
(i)
$\displaystyle -16 t^{2}+20 t=0 \Rightarrow 4 t(-4 t+5)=0$
\[t=0, t=\frac{5}{4}
\]
(ii)(a)
(iii)
At $\displaystyle \mathbf{t}=\frac{\mathbf{3}}{\mathbf{2}}, \mathbf{h}=-\mathbf{1 6} \times \frac{\mathbf{9}}{\mathbf{4}}+\mathbf{2 0} \times \frac{\mathbf{3}}{\mathbf{2}}=-\mathbf{3 6}+\mathbf{3 0}=-\mathbf{6}$
It means after $\displaystyle \frac{\mathbf{3}}{\mathbf{2}}$ seconds, dolphin has reached $\displaystyle \mathbf{6 ~ c m}$ below water level.
Speed of dolphin $\displaystyle \boldsymbol{=} \mathbf{2 0 ~ c m}$ per second.
In one second, distance covered = $\displaystyle 20$ cm
In $\displaystyle \frac{5}{4}$ seconds, distance covered $\displaystyle =20 \times \frac{5}{4}=25 \mathrm{~cm}$
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CBSE Class 10 Mathematics past-paper question from the 2023 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.