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Mathematics · 2026 · 2 marks
CBSE 2026 · Region 2 · Set 1 · Q21
If $\displaystyle \alpha, \beta$ are the zeroes of the quadratic polynomial $\displaystyle \mathrm{px}^{2}+\mathrm{qx}+\mathrm{r}$, then find the value of $\displaystyle \alpha^{3} \beta+\beta^{3} \alpha$.
Marking-scheme solution
\(\displaystyle \mathrm{px}^{2}+\mathrm{qx}+\mathrm{r}\)
\(\displaystyle \alpha+\beta=\frac{-\mathrm{q}}{\mathrm{p}}, \alpha \beta=\frac{\mathrm{r}}{\mathrm{p}}\)
\(\displaystyle \alpha^{3} \beta+\beta^{3} \alpha\)
\(\displaystyle =\alpha \beta\left(\alpha^{2}+\beta^{2}\right)\)
\(\displaystyle =\alpha \beta\left[(\alpha+\beta)^{2}-2 \alpha \beta\right]=\frac{\mathrm{r}}{\mathrm{p}}\left[\left(-\frac{\mathrm{q}}{\mathrm{p}}\right)^{2}-2\left(\frac{\mathrm{r}}{\mathrm{p}}\right)\right]\)
\(\displaystyle =\frac{\mathrm{r}}{\mathrm{p}^{3}}\left(\mathrm{q}^{2}-2 \mathrm{pr}\right)\)
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CBSE Class 10 Mathematics past-paper question from the 2026board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.