✓ Board-verified
Mathematics · 2024 · 1 mark
CBSE 2024 · Region 1 · Set 3 · Q16
If α, β are the zeroes of the polynomial 6 x^2-5 x-4, then 1/(α)+1/(β) is equal to:
If $\displaystyle \alpha, \beta$ are the zeroes of the polynomial $\displaystyle 6 x^{2}-5 x-4$, then $\displaystyle \frac{1}{\alpha}+\frac{1}{\beta}$ is equal to :
Official answer
(B)
$\displaystyle -\frac{5}{4}$
More from Polynomials
- A polynomial p(x), which has sum of its zeroes equal to their product, is:2026
- If α, β are the zeroes of the polynomial p(x)=x^2-3 x-1, then find the value of 1/(α)+1/(β).2026
- Find the zeroes of the quadratic polynomial x^2-15 and verify the relationship between the zeroes and the coefficients of the polynomial.2024
- If α, β are zeroes of the polynomial x^2-1, then value of (α+β) is:2023
- If α and β are the zeroes of the polynomial p(x)=x^2-a x-b, then the value of (α+β+α β) is equal to:2025
- If one zero of the polynomial p(x)=6 x^2+37 x-(k-2) is reciprocal of the other, then find the value of k.2023
- α and β are zeroes of a quadratic polynomial x^2-a x-b. Obtain a quadratic polynomial whose zeroes are 3 α+1 and 3 β+1.2025
- If α and β are the zeroes of the polynomial a x^2-x+c. Obtain a polynomial whose zeroes are α-3 and β-3.2025
CBSE Class 10 Mathematics past-paper question from the 2024 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.