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Mathematics · 2026 · 1 mark
CBSE 2026 · Region 5 · Set 1 · Q14
For an acute angle θ, if sin θ=1/9, then value of (9 cosec θ+1)/(9 cosec θ-1) is
For an acute angle $\displaystyle \theta$, if $\displaystyle \sin \theta=\frac{1}{9}$, then value of $\displaystyle \frac{9 \operatorname{cosec} \theta+1}{9 \operatorname{cosec} \theta-1}$ is
Official answer
(D)
$\displaystyle \frac{82}{80}$
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CBSE Class 10 Mathematics past-paper question from the 2026 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.