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Mathematics · 2026 · 2 marks
CBSE 2026 · Region 2 · Set 2 · Q24
Find the value of p, for which one zero of the quadratic polynomial px^2-14 x +8 is 6 times the other.
Find the value of $\displaystyle p$, for which one zero of the quadratic polynomial $\displaystyle \mathrm{px}^{2}-14 \mathrm{x}+8$ is $\displaystyle 6$ times the other.
Marking-scheme solution
Let the zeroes be \(\displaystyle \alpha\) and \(\displaystyle 6 \alpha\)
Sum of zeroes \(\displaystyle =\alpha+6 \alpha=\frac{14}{\mathrm{p}}\)
\(\displaystyle \Rightarrow \alpha=\frac{2}{\mathrm{p}}\)
Product of zeroes \(\displaystyle =\alpha \times 6 \alpha=\frac{8}{p}\)
\(\displaystyle \Rightarrow \quad 6 \times\left(\frac{2}{\mathrm{p}}\right)^{2}=\frac{8}{\mathrm{p}}\)
\(\displaystyle \Rightarrow \quad \mathrm{p}=3\)
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CBSE Class 10 Mathematics past-paper question from the 2026 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.