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Mathematics · 2023 · 2 marks
CBSE 2023 · Region 1 · Set 2 · Q21
Find the least number which when divided by 12, 16 and 24 leaves remainder 7 in each case.
Find the least number which when divided by $\displaystyle 12$, $\displaystyle 16$ and $\displaystyle 24$ leaves remainder $\displaystyle 7$ in each case.
Marking-scheme solution
LCM of $\displaystyle 12$, $\displaystyle 16$, $\displaystyle 24$ = $\displaystyle 48$
Required number is \(\displaystyle 48+7=55\).
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CBSE Class 10 Mathematics past-paper question from the 2023 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.