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Mathematics · 2024 · 2 marks
CBSE 2024 · Region 5 · Set 3 · Q25
Evaluate: (2 tan 30^° · sec 60^° · tan 45^°)/(1- sin^2 60^°) This section comprises Short Answer (SA) type questions of 3 marks each. 6 × 3=18
Evaluate : \[\frac{2 \tan 30^{\circ} \cdot \sec 60^{\circ} \cdot \tan 45^{\circ}}{1-\sin ^{2} 60^{\circ}} \] This section comprises Short Answer (SA) type questions of $\displaystyle 3$ marks each. $\displaystyle 6 \times 3=18$
Marking-scheme solution
\[\begin{aligned}
& \frac{2 \times \dfrac{1}{\sqrt{3}} \times 2 \times 1}{1-\dfrac{3}{4}} \\
& =\frac{16}{\sqrt{3}} \text { or } \frac{16 \sqrt{3}}{3}
\end{aligned}
\]
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CBSE Class 10 Mathematics past-paper question from the 2024 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.