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Mathematics · 2026 · 2 marks
CBSE 2026 · Region 4 · Set 1 · Q23 (b)
Evaluate: (3 cos^2 30^°-6 cosec^2 30^°)/(tan^2 60^°)
Evaluate : $\displaystyle \frac{3 \cos ^{2} 30^{\circ}-6 \operatorname{cosec}^{2} 30^{\circ}}{\tan ^{2} 60^{\circ}}$
Marking-scheme solution
\[\begin{aligned}
& \frac{3 \times\left(\dfrac{\sqrt{3}}{2}\right)^{2}-6 \times(2)^{2}}{(\sqrt{3})^{2}} \\
= & -\frac{87}{12} \text { or }-\frac{29}{4}
\end{aligned}
\]
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CBSE Class 10 Mathematics past-paper question from the 2026 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.