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Mathematics · 2026 · 2 marks
CBSE 2026 · Region 5 · Set 2 · Q22 (b)
Evaluate: (2 cos 30^°- cot^3 60^°)/(tan 30^°)
Evaluate : $\displaystyle \frac{2 \cos 30^{\circ}-\cot ^{3} 60^{\circ}}{\tan 30^{\circ}}$
Marking-scheme solution
Evaluate: $\displaystyle \frac{2 \cos 30^{\circ}-\cot ^{3} 60^{\circ}}{\tan 30^{\circ}}$ \[\begin{array}{l}
\frac{2 \cos 30^{\circ}-\cot ^{3} 60^{\circ}}{\tan 30^{\circ}}=\frac{2 \times \dfrac{\sqrt{3}}{2}-\left(\dfrac{1}{\sqrt{3}}\right)^{3}}{\dfrac{1}{\sqrt{3}}} \\
=\frac{8}{3}
\end{array}
\]
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CBSE Class 10 Mathematics past-paper question from the 2026 board exam, with the answer as CBSE’s own marking scheme gives it. Where our answers come from.