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Mathematics · 2025 · 3 marks
CBSE 2025 · Region 4 · Set 1 · Q28
P (x, y), Q (-2,-3) and R (2,3) are the vertices of a right triangle PQR right angled at P. Find the relationship between x and y. Hence, find all…
$\displaystyle \mathrm{P}(x, y), \mathrm{Q}(-2,-3)$ and $\displaystyle \mathrm{R}(2,3)$ are the vertices of a right triangle PQR right angled at P. Find the relationship between $\displaystyle x$ and $\displaystyle y$. Hence, find all possible values of $\displaystyle x$ for which $\displaystyle y=2$.
Marking-scheme solution
In \(\displaystyle \Delta \mathrm{PQR}, \angle \mathrm{P}=90^{\circ}\)
\[\begin{aligned}
& P Q^{2}+P R^{2}=Q R^{2} \\
& \Rightarrow(x+2)^{2}+(y+3)^{2}+(x-2)^{2}+(y-3)^{2}=4^{2}+6^{2} \\
& \Rightarrow x^{2}+4 x+4+y^{2}+6 y+9+x^{2}-4 x+4+y^{2}-6 y+9=52
\end{aligned}
\]
gives, \(\displaystyle x^{2}+y^{2}=13\)
Now for \(\displaystyle y=2, x= \pm 3\)
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