Physics · 2016
NEET 2016 · 1 May · Code Y · Q100
The ratio of escape velocity at earth (v_e ) to the escape velocity at a planet (v_p ) whose radius and mean density are twice as that of earth is:
The ratio of escape velocity at earth $\displaystyle \left(v_{\mathrm{e}}\right)$ to the escape velocity at a planet $\displaystyle \left(v_{\mathrm{p}}\right)$ whose radius and mean density are twice as that of earth is :
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 1: 2 \sqrt{2}$
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NEET (UG) 2016 Physics question, with the answer from NTA’s final answer key. Where our answers come from.