Physics · 2012
NEET 2012 · Mains · Code C · Q74
The ratio of amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave propagating in vacuum is equal to:
The ratio of amplitude of magnetic field to the amplitude of electric field for an electromagnetic wave propagating in vacuum is equal to :
Official answer
(4)
reciprocal of speed of light in vacuum
More from Electromagnetic Waves
- A parallel plate capacitor made of circular plates is being charged such that the surface charge density on its plates is increasing at a constant…2025
- Light with an energy flux of 25 × 10^4 Wm^-2 falls on a perfectly reflecting surface at normal incidence. If the surface area is 15 cm^2, the average…2014
- When light propagates through a material medium of relative permittivity ε_r and relative permeability μ_r, the velocity of light, v is given by: (c…2022
- Light with an average flux of 20 W / cm^2 falls on a non-reflecting surface at normal incidence having surface area 20 cm^2. The energy received by…2020
- A parallel plate capacitor is charged by connecting it to a battery through a resistor. If I is the current in the circuit, then in the gap between…2024
- An em wave is propagating in a medium with a velocity V=V i. The instantaneous oscillating electric field of this em wave is along +y axis. Then the…2018
- A capacitor of capacitance ' C ', is connected across an ac source of voltage V, given by V=V_0 sin ω t The displacement current between the plates…2021
- Out of the following options which one can be used to produce a propagating electromagnetic wave?2016
NEET (UG) 2012 Physics question, with the answer from NTA’s final answer key. Where our answers come from.