Physics · 2024
NEET 2024 · 23 June · Code C1 · Q40
The potential energy of a particle moving along x -direction varies as V=(A x^2)/(√ x +B). The dimensions of A^2/B are:
The potential energy of a particle moving along $\displaystyle x$-direction varies as $\displaystyle V=\frac{A x^2}{\sqrt{x}+B}$. The dimensions of $\displaystyle \frac{A^2}{B}$ are:
Official answer
(3)
$\displaystyle \left[\mathrm{M}^2 \mathrm{~L}^{1 / 2} \mathrm{~T}^{-4}\right]$
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NEET (UG) 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.