Physics · 2022
NEET 2022 · 4 September · Code W6 · Q37
The percentage error in the measurement of g is: (Given that.g=(4 π^2 L)/T^2, L=(10 ± 0.1) cm, T=(100 ± 1) s )
The percentage error in the measurement of $\displaystyle g$ is : (Given that $\displaystyle \left.g=\frac{4 \pi^2 L}{T^2}, L=(10 \pm 0.1) \mathrm{cm}, T=(100 \pm 1) \mathrm{s}\right)$
Official answer
(4)
$\displaystyle 3$%
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NEET (UG) 2022 Physics question, with the answer from NTA’s final answer key. Where our answers come from.