Physics · 2009
NEET 2009 · Prelims · Code A · Q46
The mean free path of electrons in a metal is 4 × 10^-8 m. The electric field which can give on an average 2 e V energy to an electron in the metal…
The mean free path of electrons in a metal is $\displaystyle 4 \times 10^{-8} m$. The electric field which can give on an average $\displaystyle 2 e V$ energy to an electron in the metal will be in units of $\displaystyle V / m$ :
Official answer
(1)
$\displaystyle 5 \times 10^7$
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NEET (UG) 2009 Physics question, with the answer from NTA’s final answer key. Where our answers come from.